3k^2-30k+27=0

Solution for 3k^2-30k+27=0 equation:

3k^2-30k+27=0

a = 3; b = -30; c = +27;
Δ = b2-4ac
Δ = -302-4·3·27
Δ = 576
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$k_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$k_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{576}=24$
$k_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-30)-24}{2*3}=\frac{6}{6}
=1
$
$k_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-30)+24}{2*3}=\frac{54}{6}
=9
$